réduire JavaScript
let array = [36, 25, 6, 15];
array.reduce((acc, curr) => acc + curr, 0)
// 36 + 25 + 6 + 15 = 82
Rick Oburu
let array = [36, 25, 6, 15];
array.reduce((acc, curr) => acc + curr, 0)
// 36 + 25 + 6 + 15 = 82var array = [36, 25, 6, 15];
array.reduce(function(accumulator, currentValue) {
return accumulator + currentValue;
}, 0); // 36 + 25 + 6 + 15 = 82reduce function sample solution// Reduce in javascript advance
// output: { '22': 2, '24': 2, '26': 1 }
const user = [
{name:"Abhishek",age:24},
{name:"Dhruval",age:22},
{name:"Anish",age:26},
{name:"Aakash",age:22},
{name:"Darshil",age:24},
]
const newUser = user.reduce((acc,cur)=>{
if(acc[cur.age]){
acc[cur.age] = acc[cur.age] +1
}
else{
acc[cur.age] = 1
}
return acc;
},{})
console.log(newUser)
//note idx and sourceArray are optional
const sum = array.reduce((accumulator, element[, idx[, sourceArray]]) => {
//arbitrary example of why idx might be needed
return accumulator + idx * 2 + element
}, 0);let fil = res.map(x=>Object.keys(x).filter(x=>x!='process' && x!='relay_type')
.reduce((a,b)=>{
a[b] = x[b]
return a
},{})).map(x=>Object.assign(x,{total:'wew'}))