JavaScript attendez que la fonction se termine
/*
* JavaScript is executed synchronously, meaning each
* line of code is executed in the order it appears in.
* To wait for a function to finish, simply call it...
* Any code after it will be called after it has
* finished.
*/
function fizzbuzz(n) {
// (this is just the most common and easy to code version)
if (n % 3 === 0 && n % 5 === 0) {
return "fizzbuzz";
} else if (n % 3 === 0) {
return "fizz";
} else if (n % 5 === 0) {
return "buzz";
}
return n;
}
console.log(fizzbuzz(15));
console.log("This code is run after `fizzbuzz` finishes");
/*
* The only exception to the above, is asynchronous
* functions. An asynchronous function is not run in sync
* with the rest of the code which is often useful. To
* run an asynchronous function synchronously, you can
* use the await keyword. Alternatively (and probably
* better in most contexts) you can use the `then` and
* `catch` methods of the promise returned by an
* asynchronous function (or just use a promise instead
* of an asynchronous function) to get the value returned
* by an asynchronous function and exectute code after it
* has run.
*/
async function fizzbuzz(n) {
if (n % 3 === 0 && n % 5 === 0) {
return "fizzbuzz";
} else if (n % 3 === 0) {
return "fizz";
} else if (n % 5 === 0) {
return "buzz";
}
throw new Error("Nice catch!");
}
fizzbuzz(15).then((res) => {
console.log(res);
console.log("This is run after `fizzbuzz` finishes (and so is the above `console.log`...)");
}).catch((err) => {
console.error(err);
console.log("This is run after `fizzbuzz` finishes (and so is the above `console.error`...)");
});
// Bonus, a more concise fizzbuzz:
const fizzbuzz = ( n ) => n % 15 ? n % 3 ? n % 5 ? n : "buzz" : "fizz" : "fizzbuzz";
MattDESTROYER
