//The findIndex() method returns the index of the first element
//in the array that satisfies the provided testing function.
//Otherwise, it returns -1, indicating that no element passed the test.
const array1 = [5, 12, 8, 130, 44];
const isLargeNumber = (element) => element > 13;
console.log(array1.findIndex(isLargeNumber));
// expected output: 3
const array1 = [5, 12, 8, 130, 44];
const search = element => element > 13;
console.log(array1.findIndex(search));
// expected output: 3
const array2 = [
{ id: 1, dev: false },
{ id: 2, dev: false },
{ id: 3, dev: true }
];
const search = obj => obj.dev === true;
console.log(array2.findIndex(search));
// expected output: 2// find index of array in javascript
const number = [1,6,2,8,1,0,4,2,7,5,4,1];
const index = number.findIndex(item => item === 8);
console.log(index)// find index of array item; test values using a function
const arr = ['A','B','C'];
const index = arr.findIndex((item) => item === 'B'); // index == 1// findIndex(callback fn)
// .... return index (when condition meets)
// .... return -1 (if condition not meets)
const array = [5, 12, 8, 130, 44];
/// it returns the index of number which satisfy the condition true
const index = array.findIndex((item)=> item>10); //1
/// now we can check what element at that index...
console.log(array[index]); // array[1]