var secondMax = function (){
var arr = [20, 120, 111, 215, 54, 78]; // use int arrays
var max = Math.max.apply(null, arr); // get the max of the array
arr.splice(arr.indexOf(max), 1); // remove max from the array
return Math.max.apply(null, arr); // get the 2nd max
};
const array = [32, 523, 5632, 920, 6000];
let largestNum = array[0];
let secondLargestNum = 0;
for(let i = 1; i < array.length; i++) {
if(array[i] > largestNum) {
secondLargestNum = largestNum;
largestNum = array[i];
}
if else (array[i] !== largestNum && array[i] > secondLargestNum) {
secondLargestNum = array[i];
}
};
console.log("Largest Number in the array is " + largestNum);
console.log("Second Largest Number in the array is " + secondLargestNum);
/* Explanation:
1) Initialize the largestNum as index of arr[0] element
2) Start traversing the array from array[1],
a) If the current element in array say arr[i] is greater
than largestNum. Then update largestNum and secondLargestNum as,
secondLargestNum = largestNum
largestNum = arr[i]
b) If the current element is in between largestNum and secondLargestNum,
then update secondLargestNum to store the value of current variable as
secondLargestNum = arr[i]
3) Return the value stored in secondLargestNum.
*/
var secondMax = function (arr){
var max = Math.max.apply(null, arr), // get the max of the array
maxi = arr.indexOf(max);
arr[maxi] = -Infinity; // replace max in the array with -infinity
var secondMax = Math.max.apply(null, arr); // get the new max
arr[maxi] = max;
return secondMax;
};const arr = ['20','120','111','215','54','78', '120'];
let intArray = arr.map(Number); // convert into number
intArray = [...new Set(intArray)]; // Remove duplicate numbers
const secondLargestNumber = intArray.sort((a,b) => {
return b - a;
})[1];
console.log(secondLargestNumber) // 120
function findSecondLargest(arr){
let largest=0, secondLargest = 0
for (i of arr){
if (i > largest){
largest = i
}
}
for (j of arr){
if(j>secondLargest && j<largest){
secondLargest = j
}
}
return secondLargest;
}
console.log("Second Largest",findSecondLargest([1,4,2,3,0]))
function nextBiggest(arr) {
let max = -Infinity, result = -Infinity;
for (const value of arr) {
const nr = Number(value)
if (nr > max) {
[result, max] = [max, nr] // save previous max
} else if (nr < max && nr > result) {
result = nr; // new second biggest
}
}
return result;
}
const arr = ['20','120','111','215','54','78'];
console.log(nextBiggest(arr));