12 jours de golf

13

Défi

À chacun des 12 jours de Noël, sortez le vers approprié de "12 jours de Noël", selon la date, sinon sortez le refrain de "Je souhaite que ce soit Noël tous les jours".

Les nouvelles lignes ( \n) de début et / ou de fin et les espaces de fin sont autorisés. Vous ne pouvez pas lire de sources externes.

Fondamentalement, ce que vous avez à faire est de lire la date du système et de sortir le verset correspondant des "12 jours de Noël".

12 jours de Noël

Les douze jours de Noël sont la saison chrétienne festive, commençant le jour de Noël (25 décembre) et se terminant le 5 janvier.

Exemples

Si la date est le 25 décembre (imprimez le plus court / premier couplet):

On the first day of Christmas 
my true love sent to me:
a Partridge in a Pear Tree

Si la date est le 31 décembre (imprimez le septième verset):

On the seventh day of Christmas
my true love sent to me:
7 Swans a Swimming
6 Geese a Laying
5 Golden Rings
4 Calling Birds
3 French Hens
2 Turtle Doves
and a Partridge in a Pear Tree

Si la date est le 5 janvier (imprimez le verset le plus long / dernier / 12ème):

On the twelth day of Christmas
my true love sent to me:
12 Drummers Drumming
11 Pipers Piping
10 Lords a Leaping
9 Ladies Dancing
8 Maids a Milking
7 Swans a Swimming
6 Geese a Laying
5 Golden Rings
4 Calling Birds
3 French Hens
2 Turtle Doves
and a Partridge in a Pear Tree

Si la date ne se situe pas dans la plage du 25 décembre au 5 janvier inclus:

Well I wish it could be Christmas every day
When the kids start singing and the band begins to play
Oh I wish it could be Christmas every day
So let the bells ring out for Christmas 

Joyeux Noel!

Beta Decay
la source
Nous devons donc écrire un programme qui lit la date du système et imprimer en conséquence? Vos questions semblent incomplètes, ne spécifiant pas autant de détails.
Optimizer
8
Encore un autre défi de compression de texte en clair? Pas un fan.
John Dvorak
Les gens de Java ne sont pas amusés, mais essaieront de se conformer.
Rodolfo Dias
3
Ce n'est pas un doublon. Ce programme était un simple défi de complexité kolmogrov - cela comprend la lecture de la date et la sortie basée sur cette lecture.

Réponses:

6

CJam, 557 550 530 528 522 519 octets

et3<(;" Christmas":P;:(31b7+372%_C<{"On the ""first second third"S/"four fif six seven eigh nin ten eleven twelf"S/"th"f++@:X=" day of"P"
my true love sent to me:
""and a Partridge in a Pear Tree."a[D,2>Sm*"Turtle Dove
French Hen
Calling Bird
Golden Ring
Geese a Lay
Swans a Swimm
Maids a Milk
Ladies Danc
Lords a Leap
Pipers Pip
Drummers Drumm"N/'s4*"ing"a7*+]z+X)<W%N*X!{4>}*}{;"Well"" I wish it could be"P" every day
"++_"When the kids start singing and the band begins to play
Oh"\"So let the bells ring out for"P}?

Testez-le ici. Pour essayer différentes dates, remplacez-les et3<(;par quelque chose comme [12 25].

Il y a probablement encore place à amélioration.

et                    "Read the current datetime as an array [year month day hour ...].":
  3<                  "Discard hours, minutes etc.";
    (;                "Discard year.";
      " Christmas":P; "Store the string in P and discard.";

:(                    "Decrement month and day.";
  31b                 "Interpret as base-31 digits. So on [12 25] we get 365 (what a coincidence).
                       On [12 31] we get 371. On [1 1] we get 0. On [1 5] we get 4.";
     7+               "Add 7.";
       372%           "Take modulo 372. Now the 12 days result in 0 to 11, others are greater.";
           _C<        "Duplicate and check if it's less than 12.";

{...}{...}?           "Run the first block for the 12 days, the second block otherwise.";

"On the 12 days:";
"On the "             "Push the string.";
"first ... third"S/   "Push first to third. Split by spaces.";
"four ... telf"S/     "Push other ordinal numbers, split by spaces.";
"th"f+                "Add th to each.";
+                     "Append to get first to twelfth.";
@:X                   "Pull day number to the top. Store in X.";
=                     "Select ordinal number.";
" day of"P            "Push ` day of Christmas`.";
"\nmy true...\n"      "Push that string, too".;
"and a Part..."a      "Push day 1 string and wrap in array.";
[                     "Remember beginning of array.";
D,2>                  "Push range [2 3 ... 12].";
Sm*                   "Append a space to each.";
"Turtle..."N/         "Push all the gifts. Split into lines.";
's4*                  "Push `ssss`.";
"ing"a7*              "Push an array with 7 copies of `ing`.";
+                     "Add the two.";
]                     "Close array, containing numbers, gifts and endings.";
z                     "Zip/transpose the array.";
+                     "Add day-1 line.";
X)                    "Push day and decrement.";
<                     "Slice off unwanted days.";
W%                    "Reverse array.";
N*                    "Join lines with line breaks.";
X!                    "Logical not of day, is 1 on day 1 and 0 on all other days.";
{4>}*                 "On day 1, remove first 4 characters (`and `).";

"On all days:";
;                     "Discard day from stack.";
"Well"                "Push the string.";
" I..."P"...day\n"    "Push the rest of the line in 3 strings.";
++_                   "Join those three into one, and duplicate.";
"When...\nOh"         "Push next line and `Oh`.";
\                     "Swap with duplicate line.";
"So ... for"P         "Push final line.";
Martin Ender
la source
5 Golden R(ing)pas acceptable? Zut! existe-t-il un moyen d'appliquer la -ingfin et la -s fin au chiffre 5?
Level River St
5

Python 2, 681 676 673 670 667 octets

import time
N=time.localtime();D,M=N.tm_mday,N.tm_mon
Q=((D<6>M<2)*(31+D)+(M>11)*D)-24
print["Well%sWhen the kids start singing and the band begins to play\nOh%sSo let the bells ring out for~"%((" I wish it could be~ every day\n",)*2),"On the %s day of~\nmy true love sent to me:\n"%("twel first second third four fif six seven eigh nin ten eleven".split()[Q%12]+"th"*(Q>3))+"\n".join("%d %s"%(i,"Turtle Doves$French Hens$Calling Birds$Golden Rings$Geese a Lay$Swans a Swimm$Maids a Milk$Ladies Danc$Lords a Leap$Pipers Pip$Drummers Drumm".split("$")[i-2]+"ing"*(i>5))for i in range(Q,1,-1))+"\nand "*(Q>1)+"a Partridge in a Pear Tree"][Q>0].replace("~"," Christmas")

J'ai essayé de jouer contre CJam ... et j'ai échoué comme prévu. Peut-être que si je pouvais comprendre comment zlib, mais je ne sais pas ...

(Merci à @FryAmTheEggman pour les suggestions via le chat)

Sp3000
la source
4

C'est gros! C'est méchant! C'est moche! Ses...

Java: 894 887 883 882 octets

Golfé:

class C{public static void main(String[]a){java.util.Calendar d=java.util.Calendar.getInstance();String p="a Partridge in a Pear Tree\n",t="Well Z\nWhen the kids start singing and the band begins to play\nOh Z\nSo let the bells ring out for X".replaceAll("Z","I wish it could be X every day"),r="";String[]s=(" day of X\nMy true love gave to me:\nçfirstçsecondçthirdçfourthçfifthçsixthçseventhçeighthçninthçtenthçeleventhçtwelfthç Turtle Doves\nç French Hens\nç Calling Birds\nç Golden Rings\nç Geese a LayY\nç Swans a SwimmY\nç Maids a MilkY\nç Ladies DancY\nç Lords a LeapY\nç Pipers PipY\nç Drummers DrummY\n").replaceAll("Y","ing").split("ç");int n=d.get(d.DAY_OF_YEAR),o=(n>358)?(n-358):(n<6)?(n+7):-1,j;if(o==-1)r=t;else{r+=("On the "+s[o]+s[0]);for(j=o+11;j-->12;r+=(j-11+s[j]));r+=(o!=1)?"and "+p:p;}System.out.print(r.replaceAll("X","Christmas"));}}

Non golfé:

class C {

    public static void main(String[] a) {
        java.util.Calendar d = java.util.Calendar.getInstance();
        String p = "a Partridge in a Pear Tree\n", t = "Well Z\nWhen the kids start singing and the band begins to play\nOh Z\nSo let the bells ring out for X".replaceAll("Z", "I wish it could be X every day"), r = "";
        String[] s = (" day of X\nMy true love gave to me:\nçfirstçsecondçthirdçfourthçfifthçsixthçseventhçeighthçninthçtenthçeleventhçtwelfthç Turtle Doves\nç French Hens\nç Calling Birds\nç Golden Rings\nç Geese a LayY\nç Swans a SwimmY\nç Maids a MilkY\nç Ladies DancY\nç Lords a LeapY\nç Pipers PipY\nç Drummers DrummY\n").replaceAll("Y", "ing").split("ç");
        int n = d.get(d.DAY_OF_YEAR), o = (n > 358) ? (n - 358) : (n < 6) ? (n + 7) : -1, j;
        if (o == -1) {
            r = t;
        } else {
            r += ("On the " + s[o] + s[0]);
            for (j = o + 11; j-- > 12; r += (j - 11 + s[j]));
            r += (o != 1) ? "and " + p : p;
        }
        System.out.print(r.replaceAll("X", "Christmas"));
    }
}

Après avoir beaucoup joué avec ça et gagné 14 octets, je pense que je vais arrêter de jouer avec.

Et oui, je sais que, les années bissextiles, mon idée peut avoir un peu de problème, mais ... c'était ma façon de couper quelques octets du code. Tant pis.

Rodolfo Dias
la source
1
Vous êtes trop dur avec Java ...
Beta Decay
1
@BetaDecay Peut-être que je le suis. Et peut-être que je devrais essayer de jouer au golf dans autre chose que Java: P
Rodolfo Dias
Pensez-vous que vous pouvez mettre en évidence la syntaxe du code sur votre code? Je préfère le code coloré au code noir et blanc. Cela m'aide à me distraire du fait que tout le code représente le code machine sous une forme ou une autre.
TheNumberOne
@TheBestOne Je le ferais avec plaisir ... si je trouvais comment l'activer.
Rodolfo Dias
3
Essayez <!-- language: lang-java -->avant un bloc de code. À utiliser <!-- language-all: lang-java -->pour tous les blocs de code de votre document. Pour plus d'informations, consultez codegolf.stackexchange.com/editing-help
TheNumberOne
1

Erlang, 748 octets

Une version propre 7 bits sans gzip-9 fait 748 octets:

f()->[maps:get(C,#{$N=>"ing",$x=>10,$q=>"th",$z=>" Christmas"},C)||C<-s(t(calendar:local_time()))].
t({{_,1,D},_})->D+7;t({{_,12,D},_})->D-24;t(_)->1.
s(X)when X<1;X>12->L=" I wish it could bez every dayx","Well"++L++"When qe kids start sNN and qe band begins to playxOh"++L++"So let qe bells rN out forz";
s(I)->"On qe "++element(I,{"first","second","qird","fourq","fifq","sixq","sevenq","eighq","ninq","tenq","elevenq","twelq"})++" day ofzxmy true love sent to me:x"++r(I).
r(0)->"";r(I)->element(I,{"a Partridge in a Pear Tree","2 Turtle Dovesxand ","3 French Hensx","4 CallN Birdsx","5 Golden RNsx","6 Geese a LayNx","7 Swans a SwimmNx","8 Maids a MilkNx","9 Ladies DancNx","10 Lords a LeapNx","11 Pipers PipNx","12 Drummers DrummNx"})++r(I-1).

Une solution gzip-9 + base64 a une longueur de 750 octets:

f()->s(t(calendar:local_time())).
t({{_,1,D},_})->D+8;t({{_,12,D},_})->D-23;t(_)->1.
s(I)->try element(I,binary_to_term(base64:decode("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")))catch _:_->s(1)end.

Une fonction Erlang encodée en UTF-8 comporte 421 caractères (935 octets).

f()->s(t(calendar:local_time())).
t({{_,1,D},_})->D+8;t({{_,12,D},_})->D-23;t(_)->1.
s(I)->try element(I,binary_to_term(<<<<(C-$㐀):14>>||C<-"哔㐀㐤䑸檷䵅焸伱㠱怶悑券摝汈佊玏㵊塐專㔒染孡㵯徵峆䫽㳳欄捐拵㟔㸽䒻焄䋓垐啂庐嚯栏奕挮浫柍濦斝憻䮽埅牃栺整䲸䔢仇椕斡㯜愹䙣㔭㘅溄暫玡乘㖐㶵廁㴠撞㰋䃟䨄㻗刚淥朞壽㖊娞泓拙母倅戒奴㸩娠㼷䶰䞦填显彻己㵲克㪐傊䈿䠛㭾悐戉压咀㲅夘䖧彤欸䡛㭭䨳吂焤擎䉲㷪㮛䡈䢙䕝欕䏛宠拎䫓巣㝐凩淄應东歹墝䧉㾘敞䃡䲜䡬㹒媽㧕勆屑憈䊱濚䇷扃滱䕝犍沿䥝犙㤐䟜㔇檗坷庈㬫焰厺憮潴䤱䍱䐉㹆㲎杒妷撯宥帶㧢夈㿤䁧䛨湽㮣庚㶠珥㯋䌛傜圵怓爜䗉姳䐙㯎槆匶煯液恄姅堭刨䬹䢃㓑喒㱿柖慾漻幜㾠丼撊挭圢㳏䎘㟰䋛冸婽灜䖠旃囦攤嵼柤含怭儿䧭㶾朿曨佰橍徰䎦䥶㟿届䇰㩌猌浀㐀㐀㐀">>))catch _:_->s(1)end.
Paul Guyot
la source
0

Javascript (665)

__=new Date("12/31");M=_.getMonth();D=_.getDate();d=M?(M==11)*(D-24):D+7;if(!d||d>12)s="Well K\nWhen the kids start singing and the bands begin to play\nOh K\nSo let the bells ring out for Christmas".replace(/K/g,"I wish it could be Christmas every day");else{for(s="On the "+"0first0second0third0fourth0fifth0sixth0seventh0eight0ninth0tenth0elevent0twelth".split(0)[d]+" day of Chirstmas\nmy true love sent to me:";--d;)s+="\n"+(d+1)+" "+"0Turtle Doves0French Hens0CallZ Birds0Golden RZs0Geese a LayZ0Swans a SwimmZ0Maids a MilkZ0Ladies DancZ0Lords a LeapZ0Pipers PipZ0Drummers DrummZ".split(0)[d].replace("Z","ing");s+="\n"+(D!=25?"and ":"")+"a Partridge in a Pear Tree"}alert(s)

Vous pouvez le tester en ajoutant des parenthèses au premier new Datechangement ie:

_=new Date;M=_...

à

_=new Date("1/5");M=_...

La voici embellie:

_ = new Date("12/31");
M = _.getMonth();
D = _.getDate();
d = M ? (M == 11) * (D - 24) : D + 7;
if (!d || d > 12) s = "Well K\nWhen the kids start singing and the bands begin to play\nOh K\nSo let the bells ring out for Christmas".replace(/K/g, "I wish it could be Christmas every day");
else {
    for (s = "On the " + "0first0second0third0fourth0fifth0sixth0seventh0eight0ninth0tenth0elevent0twelth".split(0)[d] + " day of Chirstmas\nmy true love sent to me:"; --d;) s += "\n" + (d + 1) + " " + "0Turtle Doves0French Hens0CallZ Birds0Golden RZs0Geese a LayZ0Swans a SwimmZ0Maids a MilkZ0Ladies DancZ0Lords a LeapZ0Pipers PipZ0Drummers DrummZ".split(0)[d].replace("Z", "ing");
    s += "\n" + (D != 25 ? "and " : "") + "a Partridge in a Pear Tree"
}
alert(s)
soktinpk
la source
0

C # dans Linqpad - 866 octets

Eh bien, au moins, il bat Java;) Les années bissextiles sont gérées dans le code.

Non formaté:

void Main(){var w=DateTime.Now;int y=w.Year%4,d=w.DayOfYear,c=0,p=0;string t="Well Z\nWhen the kids start singing and the band begins to play\nOh Z\nSo let the bells ring out for X".Replace("Z","I wish it could be X every day").Replace("X","Christmas"),o="On the ",x=" day of Christmas\nmy true love sent to me:\n";string[]z={"first","second","third","forth","fifth","sixth","seventh","eighth","ninth","tenth","eleventh","twelth"},b={"a Partridge in a Pear Tree\n","and ","2 Turtle Doves\n","3 French Hens\n","4 Calling Birds\n","5 Golden Rings\n","6 Geese a Laying\n","7 Swans a Swimming\n","8 Maids a Milking\n","9 Ladies Dancing\n","10 Lords a Leaping\n","11 Pipers Piping\n","12 Drummers Drumming\n"};if(y==0){p=1;}if(d>358){c=d-358-p;}else if(d<6){c=d+7;}else{t.Dump();return;}if(c==1){o+=z[0]+x+b[0];}else{o+=z[c-1]+x;for(int i=c;i>=0;i--){o+=b[i];}}o.Dump();}

Formaté:

void Main()
{
var w=DateTime.Now;
int y=w.Year%4,d=w.DayOfYear,c=0,p=0;
string t="Well Z\nWhen the kids start singing and the band begins to play\nOh Z\nSo let the bells ring out for X".Replace("Z","I wish it could be X every day").Replace("X","Christmas"),
o="On the ",x=" day of Christmas\nmy true love sent to me:\n";

string[]z={"first","second","third","forth","fifth","sixth","seventh","eighth","ninth","tenth","eleventh","twelth"},

b={"a Partridge in a Pear Tree\n","and ","2 Turtle Doves\n","3 French Hens\n","4 Calling Birds\n","5 Golden Rings\n","6 Geese a Laying\n",
"7 Swans a Swimming\n","8 Maids a Milking\n","9 Ladies Dancing\n","10 Lords a Leaping\n","11 Pipers Piping\n","12 Drummers Drumming\n"};

if(y==0)
{
    p=1;
}

if(d>358)
{
    c=d-358-p;
}
else if(d<6)
{
    c=d+7;
}
else
{
    t.Dump();
    return;
}

if(c==1)
{
    o+=z[0]+x+b[0];
}
else
{
    o+=z[c-1]+x;
    for(int i=c;i>=0;i--)
    {
        o+=b[i];
    }
}
o.Dump();
}
tsavinho
la source
Comment cela gère-t-il les années bissextiles?
Beta Decay
@BetaDecay Au début, j'utilise un module sur l'année int y=w.Year%4. Si le modulo yest 0, j'en ajoute un à cl'aide de p.
tsavinho