“Roman à entier” Réponses codées

Python romain à entier

class Solution:
    def romanToInt(self, s):
 
        values = {'I': 1, 'V': 5, 'X': 10, 'L' : 50, 'C' : 100, 'D' : 500, 'M' : 1000}   
        result = 0
        for i in range(len(s)):
            if i + 1 < len(s) and values[s[i]] < values[s[i + 1]] : # if current item is not the last item on the string
                                                                    # and current item's value is smaller than next item's value 
                result = result - values[s[i]]                      # then subtract current item's value from result
            else:
                result = result + values[s[i]]                      # otherwise add current item's value to result
        return result

Task = Solution()
print(Task.romanToInt("III"))
print(Task.romanToInt("LVIII"))
print(Task.romanToInt("MCMXCIV"))
Kingsley Atuba

Roman à entier

class Solution:
    def romanToInt(self, s):
 
        values = {'I': 1, 'V': 5, 'X': 10, 'L' : 50, 'C' : 100, 'D' : 500, 'M' : 1000}   
        result = 0
        for i in range(len(s)):
            if i + 1 == len(s) or values[s[i]] >= values[s[i + 1]] : # if current item is not the last item on the string
                                                                    # or current item's value is greater than or equal to next item's value 
                result = result + values[s[i]]                      # then add current item's value from result
            else:
                result = result - values[s[i]]                      # otherwise subtract current item's value from result
        return result

Task = Solution()
print(Task.romanToInt("III"))
print(Task.romanToInt("LVIII"))
print(Task.romanToInt("MCMXCIV"))
Kingsley Atuba

Roman à entier

Symbol       Value
I             1
V             5
X             10
L             50
C             100
D             500
M             1000
Light Lizard

Roman à entier

string[] s = { "I", "V", "X", "L", "C", "D", "M" };
            int[] r = { 1, 5, 10, 50, 100, 500, 1000 };
            string roman;
            roman = Console.ReadLine();
            int l = roman.Length;
            int n = 0;
            for (int i = 0; i < roman.Length; i++)
            {
                for (int j = 0; j < s.Length; j++)
                {
                    if (roman[i].ToString() == s[j])
                    {
                        for (int k = 0; k < s.Length; k++)
                        {
                            if (i + 1 < roman.Length)
                            {
                                if (roman[i + 1].ToString() == s[k])
                                {
                                    if (k > j)
                                    {
                                        n -= r[j];
                                    }
                                    else
                                    {
                                        n += r[j];
                                    }
                                    break;
                                }
                            }
                            else
                            {
                                n += r[j];
                                break;
                            }
                        }
                        break;
                    }
                }
            }
            Console.WriteLine(n);
Info Important

Roman à entier

var romanToInt = function (s) {

  const object = {
    'I': 1,
    'V': 5,
    'X': 10,
    'L': 50,
    'C': 100,
    'D': 500,
    'M': 1000
  }
  let count =0
  console.log(object)
 
 for(i =0; i<s.length;i++){
   const cur = object[s[i]]
   const next = object[s[i+1]]

 if(cur<next){
   count += next-cur
   i++
 }else{
   count+= cur
 }
}
return count

};
ABS

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