intersection de deux listes python
>>> a = [1,2,3,4,5]
>>> b = [1,3,5,6]
>>> list(set(a) & set(b))
[1, 3, 5]
batman_on_leave
>>> a = [1,2,3,4,5]
>>> b = [1,3,5,6]
>>> list(set(a) & set(b))
[1, 3, 5]def intersection(lst1, lst2):
lst3 = [value for value in lst1 if value in lst2]
return lst3
# Driver Code
lst1 = [4, 9, 1, 17, 11, 26, 28, 54, 69]
lst2 = [9, 9, 74, 21, 45, 11, 63, 28, 26]
print(intersection(lst1, lst2)) set(a) ^ set(b)
{2, 4, 6}# 3 Approaches to find intersect of two lists:
# set two lists:
a = [1,2,3,4,5,6,7,8]
b = [8,7,4,3,100,200]
# the intersect c should be [3,4,7,8]
# Method 1:
c = list(set(a) & set(b))
print(c)
# Method 2:
c = list(filter(set(a).__contains__, b))
print(c)
# Method 3:
c = list(set(a).intersection(b))# Python program to illustrate the intersection
# of two lists in most simple way
def intersection(lst1, lst2):
lst3 = [value for value in lst1 if value in lst2]
return lst3
# Driver Code
lst1 = [4, 9, 1, 17, 11, 26, 28, 54, 69]
lst2 = [9, 9, 74, 21, 45, 11, 63, 28, 26]
print(intersection(lst1, lst2))
# intersection of two lists (lst1 & lst2)
In [1]: x = ["a", "b", "c", "d", "e"]
In [2]: y = ["f", "g", "h", "c", "d"]
In [3]: set(x).intersection(y)
Out[3]: {'c', 'd'}
# has_intersection = bool(set(x).intersection(y)) -> True