“SQL Server définit des contraintes complexes” Réponses codées

SQL Server définit des contraintes complexes

CREATE FUNCTION dbo.fnIsAddressOwner (
  @CustomerId int,
  @AddressId int
)
RETURNS tinyint
AS
BEGIN
  DECLARE @Result tinyint
  IF EXISTS(SELECT * FROM CustomerAddresses WHERE CustomerId=@CustomerId and AddressId=@AddressId)
    SET @Result= 1
  ELSE 
    SET @Result= 0
  RETURN @Result
END


CREATE TABLE Customers (
  CustomerId int,
  PreferredAddressId int,
  CONSTRAINT ckPreferredAddressId CHECK (
    dbo.fnIsAddressOwner(CustomerId, PreferredAddressId) = 1)
  )
)