SELECT MAX(Salary) From Employee
WHERE Salary < ( SELECT Max(Salary) FROM Employee);/* sql 2nd highest salary employee */
select sal, ename
from emp
where sal =
(
select max(sal) from emp where sal <
(select max(sal) from emp)
)
----------------------------------------------- option 2
select *
from
(
select ename, sal, dense_rank() over(order by sal desc) rank
from emp
)
where rank =2;SELECT E.Employers_name, E.dep_number, E.salary
FROM Employers E
WHERE 1 = (SELECT COUNT(DISTINCT salary)
FROM Employers B
WHERE B.salary > E.salary AND E.dep_number = B.dep_number)
group by E.dep_number--Find out the name of top earner in each departments
--Output has Name, Department name and max salary of the department
SELECT E.FIRST_NAME , D.DEPARTMENT_NAME, E.SALARY
FROM EMPLOYEES E
JOIN DEPARTMENTS D ON E.DEPARTMENT_ID = D.DEPARTMENT_ID
WHERE SALARY IN(SELECT MAX(E.SALARY)
FROM EMPLOYEES E
JOIN DEPARTMENTS D ON E.DEPARTMENT_ID = D.DEPARTMENT_ID
GROUP BY DEPARTMENT_NAME);