# string [start:end:step]
string = "freeCodeCamp"
print(string[0:len(string)-1]) # freeCodeCam
print(string[0:5]) # freeC
print(string[2:6]) # eeCo
print(string[-1]) # p
print(string[-5:]) # eCamp
print(string[1:-4]) # reeCode
print(string[-5:-2]) # eCa
print(string[::2]) # feCdCmpublic class Substring {
public static void main(String[] args) {
//consider this string
//here indexing starts from 0 and space is considered as char in string
String s = "Welcome to Scaler"
//1
System.out.println("The substring is: " + str.substring(11));
//2
System.out.println("The substring is: " + str.substring(0, 7));
}
}public class Substring {
public static void main(String[] args) {
String s = "Scaler is part of Interviewbit";
System.out.println(”Hey” + s.str.substring(0, 0));
}
}# Python3 code to demonstrate working of
# Get all substrings of string
# Using list comprehension + string slicing
# initializing string
test_str = "Geeks"
# printing original string
print("The original string is : " + str(test_str))
# Get all substrings of string
# Using list comprehension + string slicing
res = [test_str[i: j] for i in range(len(test_str))
for j in range(i + 1, len(test_str) + 1)]
# printing result
print("All substrings of string are : " + str(res))def count_substring(string,sub_string):
l=len(sub_string)
count=0
for i in range(len(string)-len(sub_string)+1):
if(string[i:i+len(sub_string)] == sub_string ):
count+=1
return count