python trouver l'élément dans la liste
>>> ["foo", "bar", "baz"].index("bar")
1
Cook's Tree Boa
>>> ["foo", "bar", "baz"].index("bar")
1# There is several possible ways if "finding" things in lists.
'Checking if something is inside'
3 in [1, 2, 3] # => True
'Filtering a collection'
matches = [x for x in lst if fulfills_some_condition(x)]
matches = filter(fulfills_some_condition, lst)
matches = (x for x in lst if x > 6)
'Finding the first occurrence'
next(x for x in lst if ...)
next((x for x in lst if ...), [default value])
'Finding the location of an item'
[1,2,3].index(2) # => 1
[1,2,3,2].index(2) # => 1
[1,2,3].index(4) # => ValueError
[i for i,x in enumerate([1,2,3,2]) if x==2] # => [1, 3]l = [1, 2, 3, 4, 5, 6, 7, 8, 9]
index_of_4 = l.index(4)
print(index_of_4)
##output:
## 33 in [1, 2, 3] # => True'''
check if list1 contains all elements in list2
'''
result = all(elem in list1 for elem in list2)
if result:
print("Yes, list1 contains all elements in list2")
else :
print("No, list1 does not contains all elements in list2"