#max num in list
from functools import reduce
items = [1, 24, 17, 14, 9, 32, 2]
all_max = reduce(lambda a,b: a if (a > b) else b, items)
print (all_max) # 32# Map function
nums1 = [2,3,5,6,76,4,3,2]
sq = list(map(lambda a : a*a, nums1))
print(sq)# python code to demonstrate working of reduce()
# importing functools for reduce()
import functools
# initializing list
lis = [1, 3, 5, 6, 2, ]
# using reduce to compute sum of list
print("The sum of the list elements is : ", end="")
print(functools.reduce(lambda a, b: a+b, lis))
# using reduce to compute maximum element from list
print("The maximum element of the list is : ", end="")
print(functools.reduce(lambda a, b: a if a > b else b, lis))#The reduce() function accepts a function and a sequence and
#returns a single value calculated as follows:
#1) Initially, the function is called with the first two items from the sequence
#and the result is returned.
#2) The function is then called again with the result obtained in step 1
#and the next value in the sequence. This process keeps repeating
#until there are items in the sequence.
>>>
>>> from functools import reduce
>>>
>>> def do_sum(x1, x2): return x1 + x2
...
>>>
>>> reduce(do_sum, [1, 2, 3, 4])
10
>>>