numpy.dot
np.dot(3, 4)
12
Expensive Elk
np.dot(3, 4)
12np.dot([2j, 3j], [2j, 3j])
(-13+0j)a = [[1, 0], [0, 1]]
>>> b = [[4, 1], [2, 2]]
>>> np.dot(a, b)
array([[4, 1],
[2, 2]])