Libérer les prisonniers du lapin
from itertools import combinations
def solution(num_buns, num_required):
keyrings = [[] for num in range(num_buns)]
copies_per_key = num_buns - num_required + 1
for key, bunnies in enumerate(combinations(range(num_buns), copies_per_key)):
for bunny in bunnies:
keyrings[bunny].append(key)
return keyrings
if __name__ == "__main__":
assert all([all([x == y for x, y in zip(a, b)])
for a, b in zip([[0, 1, 2, 3, 4, 5], [0, 1, 2, 6, 7, 8], [0, 3, 4, 6, 7, 9], [1, 3, 5, 6, 8, 9], [2, 4, 5, 7, 8, 9]], solution(5, 3))])
assert all([all([x == y for x, y in zip(a, b)])
for a, b in zip([[0], [1], [2], [3]], solution(4, 4))])
Prabhu Kiran Konda