“houpsort python” Réponses codées

Comment effectuer un tri de tas, dans Python?

"""
The below code provides an implementation 
for the heap sort algorithm 
(https://en.wikipedia.org/wiki/Heapsort). 
Sorting a list via heap sort is a two-step 
process:
1. In first step, transform the original list
into a heap. 
2. In second step, sort the list by placing
the values in order at end of list. 

Let n be the number of elements in list to sort.

Time complexity: O(nlog2(n))
Space complexity: O(1), sorting is done in place.
"""
from heapq import heapify


def heap_sort(list):
    n = len(list)
    # First step: turn list into a heap
    heapify(list)
    print(list)
    # Second step: repeatedly place next
    # smallest value at end of the list
    for idx in range(n-1, 0, -1):
        swap(0, idx, list)
        bubble_down(0, idx-1, list)


def swap(idx1, idx2, list):
    list[idx1], list[idx2] = list[idx2], list[idx1]


def bubble_down(current_idx, last_idx, heap):
    # Method used to restore heap order property when violated
    child_one_idx = current_idx * 2 + 1
    while child_one_idx <= last_idx:
        child_two_idx = current_idx * 2 + 2 if current_idx*2 + 2 <= last_idx else -1

        if child_two_idx > -1 and heap[child_two_idx] < heap[child_one_idx]:
            idx_to_swap = child_two_idx
        else:
            idx_to_swap = child_one_idx

        if heap[idx_to_swap] < heap[current_idx]:
            swap(current_idx, idx_to_swap, heap)
            current_idx = idx_to_swap
            child_one_idx = current_idx * 2 + 1
        else:
            return


list = [1, 10, 4, 3, 2]
heap_sort(list)
# Descending order
print(list)  # [10, 4, 3, 2, 1]
# Ascending order
list.reverse()
print(list)  # [1, 2, 3, 4, 10]
Wissam

houpsort python

def buildHeap(lista, n):
    for i in range(n//2 - 1, -1, -1):
        heapify(lista, n, i)

def heapify(lista, n, i):
    largest = i  
    left = (2 * i) + 1    
    right = (2 * i) + 2 

    if left < n and lista[largest] < lista[left]:
        largest = left

    if right < n and lista[largest] < lista[right]:
        largest = right

    if largest != i:
        lista[i], lista[largest] = lista[largest], lista[i] 
        heapify(lista, n, largest) 

def heapSort(lista):
    n = len(lista)
    buildHeap(lista, n)
    
    for i in range(n-1, 0, -1):
        lista[i], lista[0] = lista[0], lista[i]
        heapify(lista, i, 0)
Federiko98

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