Formule de recherche interpoltaion Python
array = [5, 8, 10, 14, 22, 28, 33, 36, 39, 42, 45, 50]
# top is the upper index of the array segment we are searching, initially n = 1 or n.
top = (len(array) - 1)
print("This is top: " + str(top))
# bottomis the lower index of the array segment we are searching, intitially 0 or 1.
bottom = 0
print("This is bottom: " + str(bottom))
# Vbottom is the value in the array at index *bottom*.
Vbottom = array[bottom]
print("this is Vbottom: " + str(Vbottom))
# Vtop is the value in the array at index *top*.
Vtop = array[top]
print("this is Vtop: " + str(Vtop))
# k is the key of the item that we are seeking(i.e., the search target).
k = int(input("What is the key of the item? "))
print("This is the item we are seeking " + str(k))
# i is the array index predicted to contain key k.
i = 0
# Python3 program to implement
# interpolation search
# with recursion
# If x is present in arr[0..n-1], then
# returns index of it, else returns -1.
def interpolationSearch(arr, lo, hi, x):
# Since array is sorted, an element present
# in array must be in range defined by corner
if lo <= hi and arr[lo] <= x <= arr[hi]:
# Probing the position with keeping
# uniform distribution in mind.
TopBottom = hi - lo
kVbottom = x - arr[lo]
VtopVbottom = arr[hi] - arr[lo]
kVbottomDividedVtopVbottom = kVbottom / VtopVbottom
pos = TopBottom * kVbottomDividedVtopVbottom + lo
print(pos)
pos = int(pos)
print(pos)
# Condition of target found
if arr[pos] == x:
print("found " + str(pos))
return pos
# If x is larger, x is in right subarray
if arr[pos] < x:
print("bigger " + str(pos))
return interpolationSearch(arr, pos + 1,
hi, x)
# If x is smaller, x is in left subarray
if arr[pos] > x:
print("smaller " + str(pos))
return interpolationSearch(arr, lo,
pos - 1, x)
return -1
# Driver code
index = interpolationSearch(array, bottom, top, k)
if index != -1:
print("Element found at index", index)
else:
print("Element not found")
# This code is contributed by Hardik Jain
Wandering Wolf