“Compréhension de la liste dans Python” Réponses codées

Python de compréhension de la liste

Yes:
  result = [mapping_expr for value in iterable if filter_expr]

  result = [{'key': value} for value in iterable
            if a_long_filter_expression(value)]

  result = [complicated_transform(x)
            for x in iterable if predicate(x)]

  descriptive_name = [
      transform({'key': key, 'value': value}, color='black')
      for key, value in generate_iterable(some_input)
      if complicated_condition_is_met(key, value)
  ]

  result = []
  for x in range(10):
      for y in range(5):
          if x * y > 10:
              result.append((x, y))

  return {x: complicated_transform(x)
          for x in long_generator_function(parameter)
          if x is not None}

  squares_generator = (x**2 for x in range(10))

  unique_names = {user.name for user in users if user is not None}

  eat(jelly_bean for jelly_bean in jelly_beans
      if jelly_bean.color == 'black')
Omri Bashan

Compréhension de la liste

# Python program to demonstrate list
# comprehension in Python
   
# below list contains square of all
# odd numbers from range 1 to 10
odd_square = [x ** 2 for x in range(1, 11) if x % 2 == 1]
print (odd_square)
Outrageous Ostrich

Liste des compréhensions dans Python

[output_expression for variable in input_sequence if filter_condition]  
Shy Skunk

compréhension de la liste

S = [x**2 for x in range(10)]
V = [2**i for i in range(13)]
Breaking Bat

Compréhension de la liste

numbers = [1, 2, 3, 4, 5, 6]
squares = [i*i for i in numbers]

print(squares)
Elated Echidna

Compréhension de la liste dans Python

fruits = ["apple", "banana", "cherry", "kiwi", "mango"]
newlist = []

for x in fruits:
  if "a" in x:
    newlist.append(x)

print(newlist)
SAMER SAEID

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