Vérifiez si le numéro est uniforme ou impair
#check wheather a is odd or even
'''interactive mode
>>> 10%2
0....................False #(False==0)
>>> 5%2
1....................True #(True==1)'''
#scriptive mode
a=int(input('enter:'))
if a%2:
print("its odd")#solution gives true if 'a' value is even
else:
print("its even")#solution gives false if 'a' value is odd
print('hope it helped')
#output
#False
enter:100
its even
hope it helped
#even
enter:101
its odd
hope it helped
Gr@Y_orphan_ViLL@in##