Php Get Jour à partir de la date
$timestamp = strtotime('2009-10-22');
$day = date('D', $timestamp);
var_dump($day);
Lokesh003Coding
$timestamp = strtotime('2009-10-22');
$day = date('D', $timestamp);
var_dump($day);$today = date("d");
//Can Convert TO Int
print_r($today);// Prints the day
echo date("l") . "<br>";You can use the date function. I'm using strtotime to get the timestamp to that day ; there are other solutions, like mktime, for instance.
For instance, with the 'D' modifier, for the textual representation in three letters :
$timestamp = strtotime('2009-10-22');
$day = date('D', $timestamp);
var_dump($day);
You will get :
string 'Thu' (length=3)
And with the 'l' modifier, for the full textual representation :
$day = date('l', $timestamp);
var_dump($day);
You get :
string 'Thursday' (length=8)
Or the 'w' modifier, to get to number of the day (0 to 6, 0 being sunday, and 6 being saturday) :
$day = date('w', $timestamp);
var_dump($day);
You'll obtain :
string '4' (length=1)
// This should get you a DateTime object from the date and year.
function getDateFromDay($dayOfYear, $year) {
$date = DateTime::createFromFormat('z Y', strval($dayOfYear) . ' ' . strval($year));
return $date;
}
// This should get you the day of the year and the year in a string.
date('z Y', strtotime('21 oct 2012'));