“Java” Réponses codées

Java

DON'T DO THAT WITH YOU, go to python!
Green Team

Java

<div class="fb-page"
  data-href="https://www.facebook.com/imdb" 
  data-width="340"
  data-hide-cover="false"
  data-show-facepile="true"></div>
AKA_Mishra

Java

<div style="width: 100px;">
  <!-- Page plugin's width will be 180px -->
  <div class="fb-page" data-href="{url}" data-width="320"></div>
</div>
AKA_Mishra

Java

var isFetching: boolean = false;
Ashamed Addax

Java

3 //t
3  //n
1 3 2  //pi
2  //n
0 3  //pi
1  //n
1  //pi
1  //n
1  //pi
1  //n
2  //pi
1  //n
1  //pi
Homeless Herring

Java

// Hello World in Java

class HelloWorld {
  static public void main( String args[] ) {
    System.out.println( "Hello World!" );
  }
}
Doubtful Deer

Java

Hello, I would like to know if it is possible to somehow configure the ore for the excavator in the config?

Is it possible to change the amount of ore in the vein and its composition?
Beautiful Barracuda

Java

"java is a coding language"
ironcampanion3k

Java

# import sys
# rop=[]
# for line in sys.stdin:
#     rop.append(line.strip())
# for i in rop:
#     print(i)
    
def ratatouille():
    N, P = map(int, input().strip().split())
    R = list(map(int, input().strip().split()))
    Q = []
    for _ in range(N):
        Q.append(list(map(int, input().strip().split())))
    # print(Q,R)
    choices = []
    for i in range(N):
        for j in range(P):
            q, r = Q[i][j], R[i]
            lower = max(1, (10 * q + 11 * r - 1) // (11 * r))
            upper = (10 * q) // (9 * r)
            if lower > upper: continue
            choices.append((lower, False, i, q))
            choices.append((upper, True, i, q))
    choices.sort()

    count = 0
    quantities = [[] for _ in range(N)]
    for (_, is_upper, i, q) in choices:
        if is_upper:
            if q in quantities[i]:
                quantities[i].remove(q)
        else:
            quantities[i].append(q)
            if all(quantities):
                count += 1
                for j in range(N):
                    del quantities[j][0]
    return count

for case in range(1):
    print(ratatouille())
Adorable Addax

Java

            A1.setArregloA((Math.random()*30));
tobias pointelin

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