“BFS” Réponses codées

BFS

   vector <int> v[10] ;   //Vector for maintaining adjacency list explained above
    int level[10]; //To determine the level of each node
    bool vis[10]; //Mark the node if visited 
    void bfs(int s) {
        queue <int> q;
        q.push(s);
        level[ s ] = 0 ;  //Setting the level of the source node as 0
        vis[ s ] = true;
        while(!q.empty())
        {
            int p = q.front();
            q.pop();
            for(int i = 0;i < v[ p ].size() ; i++)
            {
                if(vis[ v[ p ][ i ] ] == false)
                {
            //Setting the level of each node with an increment in the level of parent node
                    level[ v[ p ][ i ] ] = level[ p ]+1;                 
                     q.push(v[ p ][ i ]);
                     vis[ v[ p ][ i ] ] = true;
      }
            }
        }
    }
Famous Falcon

BFS

1  procedure BFS(G, root) is
 2      let Q be a queue
 3      label root as explored
 4      Q.enqueue(root)
 5      while Q is not empty do
 6          v := Q.dequeue()
 7          if v is the goal then
 8              return v
 9          for all edges from v to w in G.adjacentEdges(v) do
10              if w is not labeled as explored then
11                  label w as explored
12                  Q.enqueue(w)
Nutty Narwhal

BFS

 1  procedure BFS(G, root) is
 2      let Q be a queue
 3      label root as discovered
 4      Q.enqueue(root)
 5      while Q is not empty do
 6          v := Q.dequeue()
 7          if v is the goal then
 8              return v
 9          for all edges from v to w in G.adjacentEdges(v) do
10              if w is not labeled as discovered then
11                  label w as discovered
12                  Q.enqueue(w)
Happy Hawk

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